Calculate the magnetic force on an electron in a magnetic field of flux density 10T, with a velocity of 3 x 10\(^7\)m/s at 60º to the magnetic field (e = 1.6 x 10\(^{-19}\)C)
- 4.8 x 10\(^{-11}\)N
- 4.6 x 10\(^{-12}\)N
-
4.16 x 10\(^{-11}\)N
- 4.3 x 10\(^{-11}\)N
The correct answer is: C
Explanation
The magnetic force on an electron in a magnetic field (F) = q v Bsin\(\theta\)
B = 10T, q = 3 x 10\(^7\)m/, \(\theta\) = 60º and q = 1.6 x 10\(^{-19}\)C
F = 1.6 x 10\(^{-19}\) x 3 x 10\(^7\) x 10 x sin 60º \(\approxeq\) 4.162 × 10\(^{-11}\)N
There is an explanation video available .