A body is pulled on a horizontal surface with a rope inclined at 30º to the vertical. If the effective force pulling the body along the horizontal surface is 15N, calculate the tension on the rope.
-
30N
- 60N
- 22.5N
- 75N
The correct answer is: A
Explanation
Effective horizontal force = 15N
T = tension on the rope
F\(_x\) = T sin\(\theta\)
15 = T x sin 30º
T = \(\frac{15}{0.5}\) = 15 x 2 = 30N.
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