The equivalent capacitance of the capacitors in the circuit above
-
\(\frac{5}{2}\)C
- 4C
- \(\frac{3}{2}\)C
- 2C
The correct answer is: A
Explanation
Capacitance in parallel = one at the top + one under = 2C
The two in the middle are in series = \(\frac{C}{2}\)
The equivalent capacitance of the capacitors in the circuit above = \(\frac{C}{2}\) + 2C = \(\frac{5}{2}\)C
There is an explanation video available .