The efficiency of a cell with internal resistance of 2\(\Omega\) supply current to a 6\(\Omega\) resistor is
- 25%
- 50%
- 65%
-
75%
The correct answer is: D
Explanation
Efficiency of a cell = \(\frac{R}{R + r }\) x 100
= \(\frac{6}{6+ 2 }\) x 100
= \(\frac{6}{8}\) x 100 = 75%
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