An accumulator is 90% efficient. If it gives out 2700J of energy while discharging, how much energy does it take in?
- 3600J
-
3000J
- 3200J
- 2430J
The correct answer is: B
Explanation
Efficiency = \(\frac{\text{ Output energy}}{\text{input energy}}\) x 100
Efficiency = 90% = 0.9, Output energy = 2700J
Input energy = \(\frac{2700}{0.9}\) = 3000J
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