Two capacitors of 0.0003μF and 0.0006μF are connected in series, find their combined capacitance.

Explanation

Combined capacitance in series = \(\frac{1}{C_T}\) = \(\frac{1}{C_1}\) +  \(\frac{1}{C_2}\) 

The two capacitors have capacitance of 0.0003μF and 0.0006μF respectively

\(\frac{1}{C_T}\) = \(\frac{1}{0.0003}\) +  \(\frac{1}{0.0006}\)  = \(\frac{0.0002 + 0.0001}{0.0006}\)

\(\frac{1}{C_T}\) = \(\frac{0.0003}{0.0006}\)

C\(_T\) = 0.0002μF.

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