0.5kg of water at 10oC is completely converted to ice by extracting 188000J of heat from it. If the specific heat capacity of water is 4200J kg-1C-1, calculate the specific latent heat of fusion of ice.
- 9.0 KJ kg-1
- 84.0 KJ kg-1
- 168.0 KJ kg-1
-
334.0 KJ kg-1
- 336.0 KJ kg-1
The correct answer is: D
Explanation
Q = mcΔθ = (0.5 x 4200 x 10) + 0.5LL = 334000