A battery of emf 24V and internal resistance 4Ω is connected to a resistor of 32Ω. What is the terminal p.d of the battery?
- 24.0V
-
21.3V
- 16.0V
- 2.7V
- 2.0V
The correct answer is: B
Explanation
E = V + IrV = E- Ir
V = 24 - {(24/36) x 4}
V = 21.3V