All the heat generated by a current of 2A passing through a resistor of 6Ω for 25s is used to evaporate 5 g of a liquid at its boiling point. What is the specific latent heat of the liquid?
- 60 Jg-1
-
120 Jg-1
- 300 Jg-1
- 360 Jg-1
- 1500 Jg-1
The correct answer is: B
Explanation
Electrical Energy = Heat Energy.
I2Rt = ml
22 x 6 x 25 = 5 x L.
L = 120 Jg-1.