A water fall is 420m high. Calculate the difference in temperature of the water between the top and bottom of the water fall. Neglect heat loses(g = 10.0m-2 specific heat capacity of water = 4.20 x 10\(^3\) JKg-1 K-1)
- 0.1oC
-
1.0oC
- 42oC
- 100oC
- 4.20oC
The correct answer is: B
Explanation
Potential Energy = Heat Energy
mgh = Mc\(\Delta \theta = \frac{gh}{c} = \frac{10 \times 240}{4.20 \times 10^3}\)
= 1.0oC