A ray of light is incident at an angle of 30o on a glass prism of refractive index 1.5. Calculate the angle through which the ray is minimally deviated in the prism. (The medium surrounding the prism is air)
-
10.5o
- 19.5o
- 21.1o
- 38.9o
- 40.5o
The correct answer is: A
Explanation
n = \(\frac{sin i}{sin r}\)sin r = \(\frac{30^o}{n}\)
sin r = \(\frac{0.5}{1.5}\)
sin r = 0.3333
r = 19.5o; Deviation 30 - 19.5 = 10.5o