If the frequency of the e.m.f. source in the a.c. circuit illustrated above is \(\frac{500}{\pi}\)Hz. What is the reactance of the inductor?
- 450
- 0.9
-
900
- 567
- 43
The correct answer is: C
Explanation
x = 2\(\pi f L = 2\pi \times \frac{500}{\pi} \times 0.9\)= 900\(\Omega\)