A body of mass m = 0.5 kg is suspended by a string and pulled by a horizontal force of 12N as shown in the diagram. Calculate the tension T in the String if the body is in equilibrium. [Take g as 10ms\(^{-1}\)]
- 7.0
- 10.9
- 12.5
-
13.0
- 17.0
The correct answer is: D
Explanation
Mg = 5N
T\(_2\) = 5\(^2\) + 12\(^2\) = 13N