Calculate the current, I in the diagram shown above.
(Neglect the internal resistance of the cell)
- 4.0A
- 2.0A
-
1.0A
- O.5A
- 0.1A.
The correct answer is: C
Explanation
R = 2 + 2 = 4 Ξ©; 1/R = ΒΌ + ΒΌ = 2/4; R = 2Ξ©β΄ I = V/R = 2/2 = 1A