A body accelerates uniformly from rest at \(2ms^{-2}\). Calculate the velocity after traveling 9m
- 36\(ms^{-1}\)
- 18\(ms^{-1}\)
-
6\(ms^{-1}\)
- 4.5\(ms^{-1}\)
- 4.24\(ms^{-1}\)
The correct answer is: C
Explanation
\(V^2= U^2+2as\) =\(0+ 2\times 2ms^{-2}\times 9 =36ms^{-1}\) thusV=\(\sqrt{36m^2s^{-2}}\) = \(6ms^{-1}\)