A metal rod of length 40cm at 20°C is heated to a temperature of 45°C….

Physics WAEC 1994

A metal rod of length 40cm at 20°C is heated to a temperature of 45°C. If the new length of the rod is 40.05cm. Calculate its linear expansitivity

  • 1.2 x \(10^{-5}K{-1}\)
  • 2.5x \(10^{-5}K{-1}\)
  • 3.5x \(10^{-5}K{-1}\)
  • 4.5x \(10^{-5}K{-1}\)
  • 5x \(10^{-5}K{-1}\) checkmark

The correct answer is: E

Explanation

\(\alpha = \frac{I_2-I_1}{I_1(\theta_2-\theta_1)} \\ \Rightarrow \frac{40.05 - 40}{40 \times (45-20)} = 5.0 \times10^{-5}\)
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