The density of a body is \(5\times10^3kgm{^-3}\) and it weighs 1N in air. Calculate the…

Physics WAEC 1994

The density of a body is \(5\times10^3kgm{^-3}\) and it weighs 1N in air. Calculate the apparent weight of the body when totally immersed in water. (Density of water =\(10^3kgm{-3}, g= 10ms^{-2}

  • 0.02N
  • 0.08N
  • 0.20N
  • 0.80N checkmark
  • 1N

The correct answer is: D

Explanation

Upthrust = weight of the water displaced =pvg= 1000 x 2 x \(10^{-5}\)=0.20N \\ Apparent weight = weight in air – upthrust = 1-0.2N=0.8N
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