The density of water is 1g\(cm^3\) while that of ice is 0.9\(cm^3\), calculate the volume change when 90g of ice is completely melted
- 0\(cm^3\)
- 9\(cm^3\)
-
10\(cm^3\)
- 90\(cm^3\)
- 100\(cm^3\)
The correct answer is: C
Explanation
V = \(\frac{m}{p} \, ice volume= 90 cm^3;water volume =100 cm^3\\Volume change = (100-90) cm^3= 10 cm^3\)