How much heat is required to convert 20 g of ice at 0oC to water at the same temperature? (Specific latent heat of ice = 336 J g-1)
- 1.35 x 103J
- 5.38 x 103J
-
6.72 x 103J
- 7.06 x 103J
- 8.06 x 103J
The correct answer is: C
Explanation
The formula of specific latent heat of fusion is given by: Q = mL
: 20 X 336
= 6720 or 6.72 X 10\(^3\)