If the current in the resistor R in diagram above is 0.05A, calculate the p.d. across the inductor.
-
2.5V
- 25.0V
- 49.0V
- 50.0V
- 250.0V
The correct answer is: A
Explanation
V= i × \(_l\)
X\(_l\) = inductive reactance → 50
I = current → 0.05A
V = 0.05 × 50
V = 2.5volt