A rocket is launched from the surface of the earth. If the radius of the earth is 6.4 x 106m and the acceleration of free fall due to gravity is 1Oms-1 calculate the escape velocity of the rocket.
- 2.53 x 104ms-1
-
1.13 x 104ms
- 8.00 x 103ms-1
- 4.23 x 103ms-1
- 6.41 x 104ms-1
The correct answer is: B
Explanation
V = √2gRV = √2 x 10 x 6.4 x 102
1.13 x 104ms