Two simple pendula x and y make 400 and 500 oscillations respectively in equal time. If the period of oscillation of x is 1.5 seconds, what is the period of oscillation of y?
- 0.53s
- 0.83s
-
1.20s
- 1.50s
- 1.88s.
The correct answer is: C
Explanation
where f = \(\frac{oscillations}{time}\)
period = 1/ f or \(\frac{time}{oscillations}\)
For pendulum x:
where period = 1.5 and oscillation = 400
time = oscillations X 1.5 = 600s
For pendulum y:
\(\frac{time}{oscillations}\) β 600/500
period for y = 1.2s
period =