A converging lens of focal length 5cm forms a virtual image which is 10cm from the lens. How far from the lens is the object?
- 2.0cm
-
3.3cm
- 5.0cm
- 10.0cm
- 15.0cm
The correct answer is: B
Explanation
\(f = \frac{uv}{u+v}\)
\(5 = \frac{-10u}{-10+u}\)
\(50 + 5u = -10u\)
\(50 = -10u - 5u\)
\(u = \frac{50}{-15}\)
u= -3.3cm