The diagram above illustrates a variation of the displacement y of a wave particle with time t. lf the velocity of wave is 250ms-1, calculate the distance between two successive particles which are in phase
- 20m
- 2.5m
- 3.0m
-
5.0m
- 50.0m
The correct answer is: D
Explanation
Time to complete one circle = 0.02secs
But, v = f\(\lambda\)
f = \(\frac{1}{f}\) = \(\frac{1}{0.02}\) = 50Hz
\(\lambda\) = \(\frac{250}{50}\) = 5m.