Calculate the amount of heat generated in an external load of resistance 8Ω if an alternating current of peak value 5A is passed through for 100s.
- 20,000J
-
10,000J
- 5,000J
- 4,000J
- 200J
The correct answer is: B
Explanation
E = I\(_{rms}\)\(^2\)Rt
I\(_{rms}\) = \(\frac{I_o}{\sqrt{2}}\) = \(\frac{5}{\sqrt{2}}\) = 3.5355
E = 12.5 x 8 x 100 = 10,000J