A ball of mass 0.1kg approaching a tennis player with a velocity of 10ms\(^{-1}\),is hit back in the opposite direction with a velocity of 15ms\(^{-1}\). If the time of impact between the racket and the ball is 0.01s, calculate the magnitude of the force with which the ball is hit
- 5000N
- 500N
-
250N
- 50N
- 25N
The correct answer is: C
Explanation
M =0.1kg; F=\(m\left(\frac{v-u}{t}\right) = 0.1\left(\frac{15-(-10)}{0.01}\right)\) F=250N