A rectangular block of wood floats in water with two-thirds of its volume immersed. When placed in another liquid, it floats with half of its volume immersed. Calculate the relative density of the liquid
- 1.43
-
1.33
- 1.00
- 0.83
- 0.75
The correct answer is: B
Explanation
from the first statement, mg = \(\frac{2}{3}Vp_wg\) ........................1
from second statement, mg = \(\frac{1}{2}Vp_lg \)...................2
equating equations 1 and 2 we have that
\(\frac{2}{3}Vp_wg\) = \(\frac{1}{2}Vp_lg\)
\(\frac{4}{3} = \frac{p_l}{p_w}\)
= 1.33