If \(\theta\) is equal to \(\alpha\) at the time the box is just about to slide down the plank, the coefficient of static friction between the plank and box is
- sin\(\alpha\)
- cos\(\alpha\)
-
tan\(\alpha\)
- sec\(\alpha\)
- cot\(\alpha\)
The correct answer is: C
Explanation
\(\mu = \frac{F}{R} = \frac{W sin \theta}{W cos q}\)= tan\(\theta\)