A piece of brass of mass 170kg has its temperature raised from 0oC to 30oC. Calculate its increase in volume, given the density of brass at 0oC as 8.5 x 103kgm3 and its cubic expansivity as 5.7 x 10-1k1
- 3.4 x 10-4m3
- 4.3 x 10-5m3
-
3.4 x 10-5m3
- 3.4 x 10-3m3
- 3.4 x 10-2m3
The correct answer is: C
Explanation
V = \(\frac{m}{p}= \frac{170}{8.5 x 10^{-3}}\) = 0.02
= \(\Delta\)\(\frac{\delta V}{V \delta T}\)
\(\delta V\) = \(\Delta\) x V x \(\delta\)T
= 5.7 x \(10^{-5}\) x 0.02 x 30
= 3.42 x \(10^{-5}\)