A waterfall is 1260m high. Calculate the change in temperature of a quantity of water that falls from the top to the bottom of the waterfall. (Neglect heat losses to the surroundings, take g as 10m-2 and specific heat capacity of water as 4200Jkg-1K-1)
- 0.3oC
-
3.0oC
- 33.3oC
- 42.0oC
- 100.0oC
The correct answer is: B
Explanation
\(\Delta t = \frac{gh}{c} = \frac{1260 \times 10}{4200}\)
= 3.0o