A converging lens of focal length 5cm is used as a magnifying glass by a man whose nearpoint is 35cm. Calculate the magnification given by the lens
- 8
- 7
-
6
- 5
- 4
The correct answer is: C
Explanation
\(\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\)= \(\frac{1}{5} - \frac{1}{35} = \frac{30}{175}\)
U = \(\frac{175}{30}\) = 5.8m
\(\frac{v}{u} = \frac{35}{5.8}\)
= 6