the shortest length of the air column in a resonance tube at resonance is 0.12m…

Physics WAEC 1998

the shortest length of the air column in a resonance tube at resonance is 0.12m and the next resonance length is 0.37m. calculate the frequency of vibration given that the speed of sound in air is 340m-1

  • 1360Hz
  • 694Hz
  • 680Hz checkmark
  • 34Hz
  • 340Hz

The correct answer is: C

Explanation

f = \(\frac{v}{2(l_2 - l_1)} = \frac{340}{2(0.37 - 0.12)} = \frac{34}{0.5}\) = 680
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