Calculate he wavelength of a note which is one octave lower than a note of 256Hz in a medium in which the speed of sound is 352ms-1
- 0.69m
-
1.38m
- 2.75m
- 5.50m
- 9.30m
The correct answer is: B
Explanation
\(\lambda\) = \(\frac{v}{f} = \frac{352}{256}\)= 1.38