A 10 Ω coil takes 21 s to melt 10g of ice at 0ºC. Assuming no heat losses, determine the current in the coil. (Specific latent heat of fusion of ice = 336 Jg\(^{-1}\))
- 16A
- 5A
-
4A
- 3A
The correct answer is: C
Explanation
Heat lost = Heat used to melt ice
I\(^2\)R t = mL
I\(^2\) x 10 x 21 = 10 x 336
I\(^2\) = \(\frac{3360}{210}\) = 16
I = \(\sqrt{16}\) = 4A.