In an electrolysis experiment, the ammeter records a steady current of 1A. The mass of copper deposited is 0.66g in 30 minutes. Calculate the error in the ammeter reading (Electrochemical equivalent of copper = 0.00033g C\(^{-1}\)).
Explanation
Mass deposited = 21t
I = \(\frac{m}{2t} = \frac{0.66}{33 \times 10^{-5} \times 30 \times 60}\)
= 1.11A
error = 1.11 - 1
= 0.11A