A wooden block of mass 1.6kg rests on a rough horizontal surface if the limiting friction force between the block and the surface is 8N. Calculate the coefficient of friction. (g = 10ms-2)
- 0.6
-
0.5
- 0.3
- 0.2
The correct answer is: B
Explanation
Limiting frictional force is proportional to normal reaction.
but R = normal reaction = mg
mass = 1.6kg
F\(_{\text{lim}}\) = 8N
g = 10m/s\(^2\)
R = 1.6 x 10 = 16N
coefficient of Friction = \(\frac{\text{F}}{\text{R}}\) = \(\frac{8}{16}\) = 0.5.