The driver of a car moving with uniform speed of 40ms-1 observes a truck approaching from the opposite direction with a speed of 20ms-1. Calculate the speed of the car relative to that of the truck
- .5ms-1
- 2.0ms-1
- 20.0ms-1
-
60.0ms-1
The correct answer is: D
Explanation
Let V\(_t\) = velocity of truck, = 20m/s V\(_c\) = velocity of car = 40m/s
\(_cV_t\) = V\(_t\) - V\(_c\) = 40 -(-20) = 40 + 20 = 60m/s