The volume and pressure of a given mass of gas at 27oC are 76cm3 and 80cm of mercury respectively. Calculate the volume at s.t.p
- 36.2cm3
-
72.8cm3
- 100.0cm3
- 808.9cm3
The correct answer is: B
Explanation
Using the general gas equation, \(\frac{ P_1 V_1}{ T_1} = \frac{ P_2 V_2}{ T_2}\)
\(V_1 = 76cm^3\), \(T_1 = 27^0C\) = 27 + 273K = 300K, \(P_1\) = 80cm, at STP \(T_2 = 0^0C\) = 273K, \(P_2\) = 76cm, \(V_2\) = ?
\(V_2 = \frac{ P_1\times V_1\times T_2}{P_2 \times T_1}\)
\(V_2 = \frac{ 80 \times 76 \times 273}{76 \times 300}\)
\(V_2 = 72.8cm^3\)