A piece of metal of mass 50g is cooled from 80oC to 20oC. Calculate the amount of heat lost. (specific heat capacity of the material of metal = 450Jkg-1K-1)
- 4.50 x 103J
- 2.25 x 103J
- 1.80 x 103J
-
1.35 x 103J
The correct answer is: D
Explanation
mass of metal = 50g = 0.05kg, c = 45Jkg\(^{-1}\)k\(^{-1}\), ΞT = 80 - 20 = 60ΒΊC
Quantity of heat lost(Q) = mass of metal x specific capacity of mass x change in temperature
Q = m x c x ΞT
Q = 0.05 x 45 x 60 = 1350J = 1.35 x 10\(^3\)J