A wave has an amplitude equal to 4.0m, angular speed \(\frac{1}{3} \pi\) rads-1 and phase angle \(\frac{2}{3} \pi\) rad. The displacement y of the wave particle is given as
-
y = 4 sin \(\frac{\pi}{3}\)(t + 2)
- y = 4 sin \(\frac{\pi}{3}\)(t + \(\frac{2}{\pi}\)
- y = 4 sin \(\frac{\pi}{3} (2t + 1)\)
- y = 4 sin \(\frac{\pi}{3}\) (t + 2)
The correct answer is: A
Explanation
y = A sin(ωt + Φ )
A = 4cm, Φ = \(\frac{2}{3} \pi \) rad, ω = \(\frac{1}{3}\pi\ rads^{-1}\)
substituting the given values
y = 4 sin ( \(\frac{1}{3}\pi\)t + \(\frac{2}{3} \pi \))
y = 4sin \(\frac{\pi}{3}\)( t + 2)