A turning fork of frequency 600Hz is sounded over a closed resonance tube. If the first and second resonant positions are 0.130m and 0.413m respectively, calculate the speed of sound in air
- 508.4ms-1
- 480.0ms-1
-
339.6ms-1
- 169.8ms-1
The correct answer is: C
Explanation
\(v = f\lambda\)
\(v = 2f \times (l_{2} - l_{1})\)
\(v = 2 \times 600 \times(0.413 - 0.130)\)
\(v = 1200 \times 0.283\)
\(v = 339.6ms^{-1}\)