calculate the inductance of an inductor whose reactance is one ohm at 50 Hz.
- 2.00 x 10-2H
- 6.36 x 10-2H
-
3.18 x 10-3H
- 4.55 x 10-2H
The correct answer is: C
Explanation
The inductive reactance (X\(_L\)) of an inductor is given by the formula:
Given: X\(_L\) = 1\(\Omega\), f = 50Hz
X\(_L\) = 2πfL
L = \(\frac{1}{2πf}\) = \(\frac{1}{2π \times50}\) = \(\frac{1}{100\pi}\) = 3.183 x 10\(^{-3}\)H