a beam PQ pivoted at P carries a load of 80N as shown above. Calculate the effort E, required to keep it horizontal. [neglect the weight of the beam]
- 32.0N
- 26.7N
- 16.0N
-
13.3N
The correct answer is: D
Explanation
E x 3 = 80 x 0.5E3 = 40
E = \(\frac{40}{3} = 13.3N\)