Surface waves travelling in deep water at 15ms-1 are incident at a shallow water boundary. If the angles of incidence and refraction are 45o and 30o respectively. Calculate the speed of the waves in shallow water
- 8.1ms-1
- 10.0ms-1
-
10.6ms-1
- 22.5ms-1
The correct answer is: C
Explanation
n = \(\frac{\sin 45}{\sin 30} = 1.4142\)n = \(\frac{15m/s}{x}\)
x = \(\frac{15}{1.4142}\) = 10.6m/s