What is the effective capacitance in the circuit?
-
2\(\mu F\)
- 6\(\mu F\)
- 18\(\mu F\)
- 216\(\mu F\)
The correct answer is: A
Explanation
\(\frac{1}{c} = \frac{1}{6} + \frac{1}{6} + \frac{1}{6}\)= \(\frac{1 + 1 + 1}{6} = \frac{3}{6} = \frac{1}{2}\)
= 2\(\mu F\)