A spiral spring of natural length 30.0cm and force constant of 20Nm-1 is compressed to 20.0cm. Calculate the energy stored in the spring
-
0.1J
- 1.0J
- 10.0J
- 100.0J
The correct answer is: A
Explanation
Energy = \(\frac{1}{2} ke^2 = \frac{1}{2} \times 20 \times 0.1^2\)= 0.1J