An object weighs 60.0N in air, 48.2N in a certain liquid X, and 44.9N in water, Calculate the relative density of X
- 3.300
- 1.279
- 0.932
-
0.782
The correct answer is: D
Explanation
R.d = Wt in Air-Wt in Air-Wt in water= \(\frac{60.0 - 48.2}{60.0 - 44.9}\)
= 0.782