An elastic string of force constant 200N m-1 is stretched through 0.8m within its elastic limit. Calculate the energy stored in the string
-
64.0J
- 80.0J
- 128.0J
- 160.0J
The correct answer is: A
Explanation
E = \(\frac{1}{2}Ke^2\)= \(\frac{1}{2} \times 200(0.8)^2 = 64J\)