A machine of velocity ratio 5 is used in lifting a load with an effort of 500N. If the machine is 80% efficient. Determine the magnitude of load
- 2500N
-
2000N
- 900N
- 625N
The correct answer is: B
Explanation
M.A = \(\frac{Eff \times V.r}{100} = \frac{80 \times 5}{100} = 4\)Load = effort x M.A
= 4 x 500 = 2000N