A ball bearing is projected vertically upwards from the ground with a velocity of 15ms-1. Calculate the time taken by the ball to return to the ground [g = 10ms-1]
- 1.5s
-
3.0s
- 5.0s
- 7.5s
The correct answer is: B
Explanation
t = 2\(\frac{(v - u)}{g} = 2\frac{(0 - 15)}{-10}\)\(\frac{2 \times 15}{10}\) = 3.0s